Plotting a simple linear inequality starts with plotting the equality. That line divides the plane into two regions – one of them satisfies the inequality.  Select any point in a region and substitute to determine whether that point satisfies the inequality. If so, then ALL points in that region satisfy the inequality.

Using my template, I graph the equality y = 2x – 2. Suppose I want to graph y < 2x – 2. Choosing any point like (3,0) will show that the region in question is below the line. So I would like to represent that visually.

Graphing y = ax + b
Rod Rodrigues 2003
	y	=	a	x	+	b
			2			-2
x	y
-1	-4
-0.5	-3
0	-2
0.5	-1
1	0
1.5	1
2	2
2.5	3
3	4
3.5	5
4	6

I will want to use the Drawing tools. If you do not see the draw tools available, you can click on the menu options View/Tool Bars/Drawing.  The drawing toolbar looks like this:

Click on Autoshapes/Lines/FreeForm
	You can now click successively around the boundary of the region in question.  When you completely come back to t he beginning, it will automatically close the region and fill it with white.
Double-click on the white to change its properties.
I will select Fill Effects, Pattern – then select a cross-hatching in blue.
I then set the transparency level to around 70%
And this will get me a traditional looking cross-hatched graph of the inequality.

The final step is to remove the borders for the strict inequality.

Right-click the chart, and re-select Chart Type. Change to a scatter plot with not lines connecting. Then double click the graphic covering the solution region and select Line/Color/No Line